In a first order reaction 20 millimole of reactant is lowered to 10 millimole in 0.3010 minute. Find rate constant of the reaction?

Step-by-step solution

For a first order reaction, the rate constant k is given by the expression: k = 2.303 t ( a a - x ) Given: Initial amount, a = 20 millimole Amount after time t , a - x = 10 millimole Time, t = 0.3010 minute Substituting the given values into the equation: k = 2.303 0.3010 ( 20 10 ) k = 2.303 0.3010 2 Using the standard value 2 = 0.3010 : k = 2.303 0.3010 0.3010 k = 2.303 minute ⁻¹ Answer: 2.303 minute ⁻¹