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MHT CET202617 April 2026Evening ShiftChemistryChemical KineticsActual

In first order reaction 20 millimole of reactant is reduced to 10 millimole in 1 151 minute. Find rate constant.

Options

  1. A0 6023 minute ⁻¹
  2. B6 120 minute ⁻¹
  3. C0 3010 minute ⁻¹
  4. D2 010 minute ⁻¹

Correct answer

A. 0 6023 minute ⁻¹

Step-by-step solution

For a first order reaction, the rate constant is given by k = 2 303 t ( a a-x ) Substituting the given values a = 20 millimole, a-x = 10 millimole, and t = 1 151 minute: k = 2 303 1 151 ( 20 10 ) k = 2 303 1 151 2 k = 2 303 0 3010 1 151 k = 0 6023 minute ⁻¹ Answer: 0 6023 minute ⁻¹

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