MHT CET202617 April 2026Evening ShiftChemistryChemical KineticsActual
For the reaction 2 NOBr _ (g) 2 NO _ (g) + Br _ 2(g) rate law is r = k[ NOBr ]^2 , if rate constant is 1 62 mol dm ⁻³ s ⁻¹ and concentration of NOBr is 2 10⁻³ mol L ⁻¹ . What is the rate of reaction ?
Options
- A4 05 10⁻⁵ mol dm ⁻³ s ⁻¹
- B6 48 10⁻⁶ mol dm ⁻³ s ⁻¹
- C2 12 10⁻⁵ mol dm ⁻³ s ⁻¹
- D8 63 10⁻⁶ mol dm ⁻³ s ⁻¹
Correct answer
B. 6 48 10⁻⁶ mol dm ⁻³ s ⁻¹
Step-by-step solution
Given rate law is r = k[ NOBr ]^2 Substituting the given values: k = 1.62 [ NOBr ] = 2 10⁻³ mol L ⁻¹ = 2 10⁻³ mol dm ⁻³ r = 1.62 (2 10⁻³)^2 r = 1.62 4 10⁻⁶ r = 6.48 10⁻⁶ mol dm ⁻³ s ⁻¹ Answer: 6 48 10⁻⁶ mol dm ⁻³ s ⁻¹