Initial concentration of reactant in a first order reaction is 0.08 ~mol dm ⁻³ What concentration would remain after 40 minute? ( given [ A ]₀ [ ~A ]_ t =5.00 )

Step-by-step solution

For a first order reaction, aligned t & = 2.303 k ₁₀ [ ~A ]₀ [ ~A ]_ t k & = 2.303 40 minute ₁₀ 5=0.04 aligned Now, array ll & 0.04= 2.303 40 ₁₀ 0.08 [ ~A ]_ t & 0.69= ₁₀(0.08)- ₁₀[ ~A ]_ t & ₁₀[ ~A ]_ t =-1.096-0.69 & ₁₀[ ~A ]_ t =-1.78 & [ ~A ]_ t = Antilog ₁₀(-1.78)=0.016 array Alternate method: aligned & Given [ A ]₀ [ ~A ]_ t =5 & [ ~A ]_ t = 0.08 5 =0.016 aligned