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MHT CET202313 May 2023Evening ShiftChemistryChemical KineticsActual

For the reaction, CH ₃ Br _ ( aq ) + OH _ ( sq ) ⁻ CH ₃ OH _ ( aq ) + Br _ ( aq ) ⁻ the rate law is rate = k [ CH ₃ Br ][ OH ] . What is change in rate of reaction if concentration of both reactants is doubled?

Options

  1. ARate increases by factor 2
  2. BRate increases by factor 4
  3. CRate remains same
  4. DRate decreases by factor 2

Correct answer

B. Rate increases by factor 4

Step-by-step solution

Rate = k [ CH ₃ Br ][ OH ]( Rate )₁= k 2 [ CH ₃ Br ] 2 [ OH ⁻ ]=4 k [ CH ₃ Br ][ OH ] (Rate )₁ Rate = 4 k [ CH ₃ Br ] [ OH ⁻ ] k [ CH ₃ Br ] [ OH ⁻ ] =4 ( Rate )₁=4 Rate

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