Calculate the rate constant of the first order reaction if 80 % of the reactant reacted in 15 minute.

Step-by-step solution

80 % of the reactant has reacted. So, if [A]₀=100 , then [A]_ t =100-80=20 aligned k & = 2.303 t ₁₀ [ A ]₀ [ ~A ]_ t & = 2.303 15 ₁₀ 100 20 & = 2.303 15 ₁₀(5) & = 2.303 15 0.699 & =0.1073 & 0.11 minute ⁻¹ aligned