MHT CET202020 Oct 2020Evening ShiftChemistryChemical KineticsActual
For the reaction 2 NOBr _ ( g ) 2 NO _ ( g ) + Br _ .2_ ( g ) ) , rate law is r = K [ NOBr ]² If rate constant is 1 62 M ⁻¹ ~s ⁻¹ and concentration of NOBr is 2 00 10⁻³ M , What is the rate of reaction?
Options
- A6 48 10⁻⁶ Ms ⁻¹
- B4 05 10⁻⁵ Ms ⁻¹
- C2 46 10⁻⁶ Ms ⁻¹
- D5 24 10⁻⁶ Ms ⁻¹
Correct answer
A. 6 48 10⁻⁶ Ms ⁻¹
Step-by-step solution
2 NOBr _ ( g ) 2 NO _ ( g ) + Br _ 2( ~g ) , k =1.62 ~M ⁻¹ ~s ⁻¹,[ NOBr ]=2.00 10⁻³ ~M Now, r = k [ NOBr ]² r =1.62 ~M ⁻¹ ~s ⁻¹ (2.00 10⁻³ )² M ² r =6.48 10⁻⁶ ~M ~s ⁻¹