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MHT CET2019Evening ShiftChemistryChemical KineticsActual

For a chemical reaction rate law is, rate = K A 2 B . If [A] is doubled at constant B , the rate of reaction.

Options

  1. AIncrease by a factor of 8
  2. BIncrease by a factor of 4
  3. CIncreases by a factor of 3
  4. DIncreases by a factor of 2

Correct answer

B. Increase by a factor of 4

Step-by-step solution

Given, Initial rate = k A 2 B If A 1 = 2 A Rate k = 2 A 2 B = 4 k A 2 B Thus, if the concentration of A , A is doubled and that of B is constant, then initial rate increases by a factor of 4 .

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