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MHT CET2018ChemistryChemical Kinetics

Slope of the straight line obtained by plotting log 10 ⁡ k against 1 T represents which term?

Options

  1. A- E a
  2. B- 2.303 E a ∕ R
  3. C- E a /( 2.303 R)
  4. D- E a ∕ R

Correct answer

C. - E a /( 2.303 R)

Step-by-step solution

K = Ae - Ea / (RT) Apply log on both sides: ln k = ln A - E a RT log k = log A - E a 2.303 R × 1 T y = mx + C y = log k , x = 1 T , Slope (m) = - E a 2.303 R

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