What type of hybridization is found in [ Ni ( Cl )₄]²⁻ ?

Step-by-step solution

The given complex is [ NiCl ₄]²⁻ . Let the oxidation state of Ni be x . x + 4(-1) = -2 x = +2 The electronic configuration of neutral Ni is [ Ar ] 3d^8 4s^2 . The electronic configuration of Ni ²⁺ is [ Ar ] 3d^8 . Cl ⁻ is a weak field ligand, so it does not cause the pairing of electrons in the 3d orbitals of Ni ²⁺ . To accommodate the four electron pairs donated by the four Cl ⁻ ligands, the Ni ²⁺ ion undergoes hybridization using one 4s and three 4p empty orbitals. Therefore, the hybridization involved is sp^3 ,