The sum of coordination number and oxidation number of M in [ M(en) ₂ C ₂ O ₄] Cl is

Step-by-step solution

In the given complex [ M(en) ₂ C ₂ O ₄] Cl , the ligands present inside the coordination sphere are ethylenediamine (en) and oxalate ( C ₂ O ₄²⁻ ). Both ethylenediamine and oxalate are bidentate ligands. Coordination number of M = 2 2 (from en) + 1 2 (from oxalate) = 4 + 2 = 6 . To find the oxidation number of M, let its oxidation state be x . The charge on ethylenediamine is 0 , the charge on oxalate is -2 , and the charge on the chloride ion outside the coordination sphere is -1 . Equating the sum of oxidation st