MHT CET202613 April 2026Evening ShiftChemistryCoordination CompoundsActual
Which of the following statements is correct with respect to [ Mn(CN) ₆]³⁻ ?
Options
- AIt is sp^3 d^2 hybridised and tetrahedral.
- BIt is d^2 sp^3 hybridised and octahedral.
- CIt is dsp^2 hybridised and square planar
- DIt is sp^3 d^2 hybridised and octahedral.
Correct answer
B. It is d^2 sp^3 hybridised and octahedral.
Step-by-step solution
The given complex is [ Mn(CN) ₆]³⁻ . Let the oxidation state of Mn be x . x + 6(-1) = -3 x = +3 The electronic configuration of Mn is [ Ar ] 3d^5 4s^2 . The electronic configuration of Mn ³⁺ is [ Ar ] 3d^4 . Since CN ^- is a strong field ligand, it causes pairing of electrons in the 3d orbitals against Hund's rule. The four electrons occupy the t_ 2g orbitals, leaving two e_g orbitals empty. These two empty 3d orbitals, along with one 4s and three 4p orbitals, undergo d^2sp^3 hybridization. The geometry correspondi