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MHT CET202618 April 2026Evening ShiftChemistryd and f Block ElementsActual

Which lanthanoid from following exhibits f¹⁴ configuration in +3 state?

Options

  1. ATm
  2. BLu
  3. CCe
  4. DDy

Correct answer

B. Lu

Step-by-step solution

The electronic configuration of Lutetium (Lu), which has an atomic number of 71 , is [ Xe ] 4f¹⁴ 5d¹ 6s² . In the +3 oxidation state, Lu loses two electrons from the 6s orbital and one electron from the 5d orbital. Therefore, the electronic configuration of Lu ³⁺ is [ Xe ] 4f¹⁴ . For the other given elements in their +3 state: Tm ³⁺ ( Z=69 ) has the configuration [ Xe ] 4f¹² . Ce ³⁺ ( Z=58 ) has the configuration [ Xe ] 4f¹ . Dy ³⁺ ( Z=66 ) has the configuration [ Xe ] 4f⁹ . Answer: Lu

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