Which from following pair of elements in their respective oxidation states develops same value of calculated spin only magnetic moment ?

Step-by-step solution

The spin-only magnetic moment is given by = n(n+2) BM, where n is the number of unpaired electrons. Electronic configuration of Ti ³⁺ is [ Ar ] 3d¹ , so n = 1 . Electronic configuration of Zn ²⁺ is [ Ar ] 3d¹⁰ , so n = 0 . Electronic configuration of Cr ²⁺ is [ Ar ] 3d⁴ , so n = 4 . Electronic configuration of Fe ²⁺ is [ Ar ] 3d⁶ , so n = 4 . Electronic configuration of Cr ³⁺ is [ Ar ] 3d³ , so n = 3 . Electronic configuration of Cu ²⁺ is [ Ar ] 3d⁹ , so n = 1 . Since both Cr ²⁺ and Fe ²⁺ have 4 unpaired electrons,