MHT CET202613 April 2026Evening ShiftChemistryd and f Block ElementsActual
Which of the following ions exhibit same value of spin only magnetic moment? (A). Ti ³⁺ (B). Cr ³⁺ (C). Mn ²⁺ (D). Fe ³⁺ (E). Sc ³⁺ Choose the most appropriate answer from the options given below.
Options
- A(B) and (D) only
- B(A) and (E) only
- C(C) and (D) only
- D(A) and (D) only
Correct answer
C. (C) and (D) only
Step-by-step solution
Electronic configuration of the given ions and their number of unpaired electrons ( n ): Ti ³⁺ : [ Ar ] 3d^1 n = 1 Cr ³⁺ : [ Ar ] 3d^3 n = 3 Mn ²⁺ : [ Ar ] 3d^5 n = 5 Fe ³⁺ : [ Ar ] 3d^5 n = 5 Sc ³⁺ : [ Ar ] 3d^0 n = 0 The spin-only magnetic moment is given by = n(n+2) BM. Since Mn ²⁺ and Fe ³⁺ have the same number of unpaired electrons ( n = 5 ), they exhibit the same spin-only magnetic moment of 35 BM. Therefore, (C) and (D) only is the correct choice. Answer: (C) and (D) only