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MHT CET202526 Apr 2025Evening ShiftChemistryd and f Block ElementsActual

What is the number of unpaired electrons in f orbitals of lutetium in its +3 oxidation state?

Options

  1. A7
  2. B5
  3. C4
  4. D0(zero)

Correct answer

D. 0(zero)

Step-by-step solution

Lutetium (Lu, Z=71) has the electron configuration [ Xe ] 4f¹⁴ 5d^1 6s^2 . In the Lu³⁺ ion, three electrons are removed, yielding the configuration [ Xe ] 4f¹⁴ . The f¹⁴ configuration represents a fully filled subshell with all 14 electrons paired, resulting in 0 unpaired electrons in the f orbitals.

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