MHT CET202620 April 2026Evening ShiftChemistryElectrochemistryActual
Determine the electrode potential of Sn ²⁺(0.01 M ) | Sn(s) at 25^ C if E^ _ Sn is -0.136 V.
Options
- A0.186 V
- B-0.186 V
- C-0.195 V
- D0.195 V
Correct answer
C. -0.195 V
Step-by-step solution
The reduction half-reaction is Sn ²⁺ + 2e⁻ Sn(s) . Using the Nernst equation: E = E^ - 0.0591 n 1 [ Sn ²⁺] Substituting the given values ( n = 2 , [ Sn ²⁺] = 0.01 M , E^ = -0.136 V ): E = -0.136 - 0.0591 2 1 0.01 E = -0.136 - 0.02955 (100) E = -0.136 - 0.02955 2 E = -0.136 - 0.0591 E = -0.1951 V -0.195 V Answer: -0.195 V