MHT CET202619 April 2026Morning ShiftChemistryElectrochemistryActual
What is the conductivity of 0.02 M AgNO ₃ solution having cell constant 1.2 cm ⁻¹ and resistance 95.0 ohms ?
Options
- A1.140 10⁻² ⁻¹ cm ⁻¹
- B1.263 10⁻² ⁻¹ cm ⁻¹
- C1.340 10⁻² ⁻¹ cm ⁻¹
- D1.463 10⁻² ⁻¹ cm ⁻¹
Correct answer
B. 1.263 10⁻² ⁻¹ cm ⁻¹
Step-by-step solution
Given: Resistance, R = 95.0 Cell constant, G^ * = 1.2 cm ⁻¹ The conductivity is given by the relation: = 1 R G^ * Substituting the given values: = 1 95.0 1.2 = 0.01263 ⁻¹ cm ⁻¹ = 1.263 10⁻² ⁻¹ cm ⁻¹ Answer: 1.263 10⁻² ⁻¹ cm ⁻¹