If the emf of cell, Cu _ (s) Cu ²⁺_ (1M) | Ag ⁺_ (1M) Ag is 0.463 V at 25 ^ C and standard potential of Cu electrode is 0.337 V. Find the standard potential of Ag electrode

Step-by-step solution

The cell representation is Cu _ (s) Cu ²⁺_ (1M) | Ag ⁺_ (1M) Ag . Since the concentrations of the ions are 1 M , the given emf is the standard emf of the cell, E^ _ cell = 0.463 V . The standard reduction potential of the anode (Cu) is E^ _ Cu ²⁺/ Cu = 0.337 V . Using the relation for standard cell potential: E^ _ cell = E^ _ cathode - E^ _ anode E^ _ cell = E^ _ Ag ⁺/ Ag - E^ _ Cu ²⁺/ Cu Substituting the given values: 0.463 = E^ _ Ag ⁺/ Ag - 0.337 E^ _ Ag ⁺/ Ag = 0.463 + 0.337 = 0.800 V The standard potential of t