Calculate the concentration of silver nitrate solution if molar conductivity and conductivity of silver nitrate at 25^ C are respectively 120 ohm ⁻¹ cm ^2 mol ⁻¹ and 0.0024 ohm ⁻¹ cm ⁻¹ .

Step-by-step solution

The relationship between molar conductivity _m , conductivity , and concentration C in molarity is given by: _m = 1000 C Rearranging the formula to solve for concentration C : C = 1000 _m Substituting the given values = 0.0024 ohm ⁻¹ cm ⁻¹ and _m = 120 ohm ⁻¹ cm ^2 mol ⁻¹ : C = 0.0024 1000 120 C = 2.4 120 C = 0.02 M Answer: 0.02 M