MHT CET202615 April 2026Morning ShiftChemistryElectrochemistryActual
The molar conductivity of 0.04 M AB ₂ type salt solution at 300 K is 200 , ⁻¹ cm ^2 mol ⁻¹ . Find the conductivity.
Options
- A0.006 , ⁻¹ cm ⁻¹
- B0.008 , ⁻¹ cm ⁻¹
- C0.01 , ⁻¹ cm ⁻¹
- D0.015 , ⁻¹ cm ⁻¹
Correct answer
B. 0.008 , ⁻¹ cm ⁻¹
Step-by-step solution
The relation between molar conductivity _m , conductivity , and molarity M is given by: _m = 1000 M Given: _m = 200 , ⁻¹ cm ^2 mol ⁻¹ M = 0.04 M Substituting the given values into the formula: 200 = 1000 0.04 = 200 0.04 1000 = 8 1000 = 0.008 , ⁻¹ cm ⁻¹ Answer: 0.008 , ⁻¹ cm ⁻¹