MHT CET202613 April 2026Morning ShiftChemistryElectrochemistryActual
Calculate the molar conductivity of 0.2 M KCl solution at 298 K ( k = 0.0248 ⁻¹ cm ⁻¹ )
Options
- A143 ⁻¹ cm ^2 mol ⁻¹
- B98 ⁻¹ cm ^2 mol ⁻¹
- C124 ⁻¹ cm ^2 mol ⁻¹
- D87 ⁻¹ cm ^2 mol ⁻¹
Correct answer
C. 124 ⁻¹ cm ^2 mol ⁻¹
Step-by-step solution
Given concentration C = 0.2 M and conductivity k = 0.0248 ⁻¹ cm ⁻¹ . The formula for molar conductivity is _m = k 1000 C . Substituting the given values: _m = 0.0248 1000 0.2 _m = 24.8 0.2 = 124 ⁻¹ cm ^2 mol ⁻¹ . Answer: 124 ⁻¹ cm ^2 mol ⁻¹