Match List I with List II. List I (Conversion) List II (Number of Faraday required) A. 1 mole of H ₂ O to O ₂ I. 3F B. 1 mol of MnO ₄^- to Mn ²⁺ II. 2F C. 1.5 mol of Ca from molten CaCl ₂ III. 1F D. 1 mol of FeO to Fe ₂ O ₃ IV. 5F Choose the correct answer from the options given below :

Step-by-step solution

In conversion A, H₂O 1 2 O₂ + 2H^+ + 2e^- , the charge required for 1 mole of H₂O is 2F . In conversion B, MnO₄^- + 8H^+ + 5e^- Mn²⁺ + 4H₂O , the oxidation state of Mn changes from +7 to +2 , so the charge required for 1 mole of MnO₄^- is 5F . In conversion C, Ca²⁺ + 2e^- Ca , the charge required for 1 mole of Ca is 2F . Therefore, the charge required for 1.5 moles of Ca is 1.5 2F = 3F . In conversion D, Fe²⁺ Fe³⁺ + e^- , the oxidation state of Fe changes from +2 in FeO to +3 in Fe₂O₃ , so the charge required for 1