What product is obtained by electrolysis of 50 % solution of sulfuric acid on further hydrolysis?

Step-by-step solution

Electrolysis of a 50 % sulfuric acid solution produces peroxodisulfuric acid ( H₂S₂O₈ ) at the anode through the oxidation reaction: 2SO₄²⁻ S₂O₈²⁻ + 2e^- , followed by protonation: S₂O₈²⁻ + 2H^+ H₂S₂O₈ . Hydrolysis of H₂S₂O₈ proceeds via two steps: initial conversion to peroxymonosulfuric acid ( H₂SO₅ ) with H₂S₂O₈ + H₂O H₂SO₅ + H₂SO₄ , followed by decomposition to hydrogen peroxide with H₂SO₅ + H₂O H₂SO₄ + H₂O₂ . The final product is therefore hydrogen peroxide ( H₂O₂ ), corresponding to option D .