What is reduction potential of hydrogen gas electrode when pure hydrogen gas is at 1 atmospheric pressure and platinum electrode is in contact with HCl solution of PH 1 at 298 K ?

Step-by-step solution

The reduction potential for the hydrogen electrode under specified conditions is determined using the Nernst equation: E_ red = E^0_ red - 0.0592 n P_ H₂ [H^+]^2 Substituting E^0_ red = 0 V , P_ H₂ = 1 atm , and n = 2 , with [H^+] = 10^ - pH = 10⁻¹ M , yields: E_ red = - 0.0592 2 1 (10⁻¹)^2 = - 0.0592 2 (10^2) Simplifying the logarithmic term, (10^2) = 2 , results in: E_ red = -0.0592 V Final answer: B