What is the charge required to convert 2 ~mol KMnO ₄ to MnSO ₄ ?

Step-by-step solution

Oxidation state analysis: In KMnO ₄ , potassium contributes +1 and oxygen contributes -8 , so manganese must be +7 . In MnSO ₄ , manganese is +2 to balance the SO ₄²⁻ ion. Manganese undergoes reduction from +7 to +2 , gaining 5 electrons per ion. n_ electrons = 7 - 2 = 5 mol e ^- per mol Mn For each mole of KMnO ₄ , 5 Faradays of charge are required. With 2 moles of reactant: Q = 2 5 = 10 F The required charge is 10 F .