A hypothetical galvanic cell is _ A _ ( s ) | A ⁺(1 M ) | | B ⁺²(1 M ) | B _ ( s ) ^ and emf of cell is positive. What is the possible cell reaction?

Step-by-step solution

Cell notation: _ A _ ( s ) | A ⁺(1 M )|| B ⁺²(1 M )| B _ ( s ) ^ The anode (left side) shows oxidation of A to A ⁺ , while the cathode (right side) shows reduction of B ²⁺ to B . The oxidation half-reaction is A _ ( s ) A ⁺_ ( aq ) + e ⁻ , and the reduction half-reaction is B ²⁺_ ( aq ) + 2 e ⁻ B _ ( s ) . To balance electrons, multiply the oxidation half-reaction by 2: 2 A _ ( s ) 2 A ⁺_ ( aq ) + 2 e ⁻ . Combining both half-reactions gives 2 A _ ( s ) + B ²⁺_ ( aq ) 2 A ⁺_ ( aq ) + B _ ( s ) , which matches option