MHT CET202523 Apr 2025Morning ShiftChemistryElectrochemistryActual
What is value of E_ cell at 298 K for the reaction, Zn _ ( s ) + Cu ⁺²(0 1 M ) Zn ⁺²(0 1 M )+ Cu _ ( s ) if E _ cell ^ =1 1 ~V ?
Options
- A1.1 V
- B0.11 V
- C1.0408 V
- D0.0296 V
Correct answer
A. 1.1 V
Step-by-step solution
The cell potential is determined using the Nernst equation: E_ cell = E_ cell ^ - 0.0592 n Q For the reaction Zn _ ( s ) + Cu ⁺²(0.1 M ) Zn ⁺²(0.1 M )+ Cu _ ( s ) with E_ cell ^ = 1.1 V , the number of electrons transferred is n = 2 . The reaction quotient is Q = [ Zn ⁺²] / [ Cu ⁺²] = 0.1 / 0.1 = 1 . Substituting into the Nernst equation: E_ cell = 1.1 - 0.0592 2 1 Since 1 = 0 , the second term vanishes, yielding E_ cell = 1.1 V . Final answer: A