MHT CET202521 Apr 2025Evening ShiftChemistryElectrochemistryActual
If E ^ ( Ag ⁺ _ ( aq ) Ag _ ( s ) )=+0.80 ~V What is potential developed for Ag _ ( s ) Ag ⁺¹(0 01 M )+ e at 298 K ?
Options
- A+0.9184 ~V
- B-0.9184 ~V
- C+0.6816 ~V
- D-0.6816 ~V
Correct answer
D. -0.6816 ~V
Step-by-step solution
The reduction potential for Ag ⁺_ ( aq ) + e⁻ Ag _ ( s ) is E^ = +0.80 V . For the reverse oxidation reaction Ag _ ( s ) Ag ⁺(0.01 M ) + e⁻ , the standard potential becomes E^ = -0.80 V . The Nernst equation E = E^ - 0.0592 n Q applies, with n = 1 and Q = [ Ag ⁺] = 0.01 M . Substituting gives E = -0.80 - 0.0592 (10⁻²) = -0.80 - 0.0592 (-2) = -0.80 + 0.1184 = -0.6816 V . Final answer: D