The resistance of conductivity cell filled with 0.1 M KCl solution is 100 ohm and conductivity is 1.70 10⁻⁴ ~S ~cm ⁻¹ . What is the cell constant of the cell?

Step-by-step solution

G^*= R Where: - G^* is the cell constant ( cm ⁻¹ ) , - is the conductivity ( S cm ⁻¹ ) , - R is the resistance ( ) . Given: - =1.70 10⁻⁴ ~S ~cm ⁻¹ , - R=100 . Calculation: G^*= (1.70 10⁻⁴ ) 100=0.017 ~cm ⁻¹ Final Answer: The cell constant is: 0.017 ~cm ⁻¹ Hence, the correct option is (2) 0.017 ~cm ⁻¹ .