MHT CET20249 May 2024Evening ShiftChemistryElectrochemistryActual
Resistance and conductivity of a cell containing 0.1 M KCl solution at 298 K are 115 ohm and 1.90 10⁻⁶ ~S ~cm ⁻¹ respectively. What is the value of cell constant?
Options
- A0.165 ~cm ⁻¹
- B1.601 ~cm ⁻¹
- C2.185 ~cm ⁻¹
- D0.218 ~cm ⁻¹
Correct answer
D. 0.218 ~cm ⁻¹
Step-by-step solution
- Resistance: 115 ohm - Conductivity: 1.90 10⁻⁶ ~S ~cm ⁻¹ - Formula to find the cell constant ( l a ) : l a =k R where k is the conductivity and R is the resistance. Given Data: - k=1.90 10⁻⁶ S⁻¹ - R=115 Calculation: Substituting the given values into the formula: l a = (1.90 10⁻⁶ ) 115=0.2185 ~cm ⁻¹ Answer: The cell constant is approximately 0.2185 ~cm ⁻¹ , which matches with Option 4: 0.218 ~cm ⁻¹ .