MHT CET20244 May 2024Morning ShiftChemistryElectrochemistryActual
The conductivity of 0.005 M NaI solution at 25^ C is 6.07 10⁻⁴ ⁻¹ ~cm ⁻¹ . Calculate its molar conductivity
Options
- A121.4 ⁻¹ ~cm ^2 ~mol ⁻¹
- B110.1 ⁻¹ ~cm ^2 ~mol ⁻¹
- C201.1 ⁻¹ ~cm ^2 ~mol ⁻¹
- D241.4 ⁻¹ ~cm ^2 ~mol ⁻¹
Correct answer
A. 121.4 ⁻¹ ~cm ^2 ~mol ⁻¹
Step-by-step solution
aligned _ m & = 1000 k c = 1000 ~cm ^3 ~L ⁻¹ 6.07 10⁻⁴ ⁻¹ ~cm ⁻¹ 0.005 ~mol ~L ⁻¹ & =121.4 ⁻¹ ~cm ^2 ~mol ⁻¹ aligned