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MHT CET20243 May 2024Evening ShiftChemistryElectrochemistryActual

What is the cell constant, if two platinum electrodes in conductivity cell are separated by 0.92 cm and area of cross section is 1.2 ~cm ^2 ?

Options

  1. A0.767 ~cm ⁻¹
  2. B0.906 ~cm ⁻¹
  3. C1.304 ~cm ⁻¹
  4. D1.104 ~cm ⁻¹

Correct answer

A. 0.767 ~cm ⁻¹

Step-by-step solution

Cell constant = l a = 0.92 ~cm 1.2 ~cm ^2 =0.767 ~cm ⁻¹

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