MHT CET20243 May 2024Morning ShiftChemistryElectrochemistryActual
The molar conductivity of 0.02 M KCl solution is 410 ⁻¹ ~cm ^2 ~mol ⁻¹ at 25^ C . Calculate its conductivity?
Options
- A8.2 10⁻³ ⁻¹ ~cm ⁻¹
- B2.8 10⁻³ ⁻¹ ~cm ⁻¹
- C4.1 10⁻³ ⁻¹ ~cm ⁻¹
- D5.4 10⁻³ ⁻¹ ~cm ⁻¹
Correct answer
A. 8.2 10⁻³ ⁻¹ ~cm ⁻¹
Step-by-step solution
aligned _ m & = 1000 k c k & = _ m c 1000 = 410 ⁻¹ ~cm ^2 ~mol ⁻¹ 0.02 ~mol dm ⁻³ 1000 ~cm ^3 dm ⁻³ & =8.2 10⁻³ ⁻¹ ~cm ⁻¹ aligned