An organic monobasic acid has dissociation constant 2.25 10⁻⁶ . What is percent dissociation in its 0.01 M solution?

Step-by-step solution

K _ a =2.25 10⁻⁶ For a weak monobasic acid, aligned = K _ a c = 2.25 10⁻⁶ 0.01 = 2.25 10⁻⁴ =0.015 Percent dissociation = 100 =0.015 100=1.5 % aligned