MHT CET202314 May 2023Morning ShiftChemistryElectrochemistryActual
Which from following expressions is used to find the cell potential of Cd _ (s) | Cd _ (aq) ⁺⁺ | | Cu _ (aq) ⁺⁺ | Cu _ (s) cell at 25^ C ?
Options
- AE _ cell = E _ cell ^ o -0.0296 [ Cd ⁺⁺ ] [ Cu ⁺⁺ ]
- BE _ cell = E _ cell ^ o +0.0296 [ Cd ⁺⁺ ] [ Cu ⁺⁺ ]
- CE _ cell = E _ cell ^ o -0.0592 [ Cu ⁺⁺ ] [ Cd ⁺⁺ ]
- DE _ cell = E _ cell ^ o +0.0592 [ Cu ⁺⁺ ] [ Cd ⁺⁺ ]
Correct answer
A. E _ cell = E _ cell ^ o -0.0296 [ Cd ⁺⁺ ] [ Cu ⁺⁺ ]
Step-by-step solution
Cell reaction: aligned & Cd _ ( s ) Cd _ ( aq ) ²⁺+2 e ⁻ (oxidation at anode) & Cu _ ( aq ) ²⁺+2 e ⁻ Cu _ ( s ) (reduction at cathode) & Cd _ ( s ) + Cu _ ( aq ) ²⁺ Cd _ ( aq ) ²⁺+2 Cu _ ( s ) & (overall reaction) aligned Now, aligned E _ cell & = E _ cell ^ o - 0.0592 ~V n ₁₀ [ Product ] [ Reactant ] & =0.02- 0.0592 ~V 2 ₁₀ [ Cd ⁺⁺ ] [ Cu ⁺⁺ ] & = E _ cell ^ -0.0296 [ Cd ⁺⁺ ] [ Cu ⁺⁺ ] aligned