Calculate the time required in second to deposit 6.35 ~g copper from its salt solution by passing 5 ampere current. [Molar mass of Cu =63.5 ~g ~mol ⁻¹ ]

Step-by-step solution

aligned & Cu _ ( s ) ²⁺+2 e ⁻ Cu _ ( s ) & Mole ratio = 1 ~mol 2 ~mole ⁻ & W = I ( A ) t ( s ) 96500 ( C / mol e ⁻ ) mole ratio molar mass & 6.35 ~g = 5 t 96500 ( C / mol e ⁻ ) 1 ~mol 2 ~mol e 63.5 ~g ~mol ⁻¹ & t = 6.35 96500 2 5 63.5 =3860 seconds aligned