MHT CET202310 May 2023Morning ShiftChemistryElectrochemistryActual
Conductivity of a solution is 1.26 10⁻² ⁻¹ ~cm ⁻¹ . Calculate molar conductivity for 0.01 M solution.
Options
- A1.26 10^3 ⁻¹ ~cm ^2 ~mol ⁻¹
- B2.52 10^3 ⁻¹ ~cm ^2 ~mol ⁻¹
- C4.82 10^3 ⁻¹ ~cm ^2 ~mol ⁻¹
- D6.30 10^3 ⁻¹ ~cm ^2 ~mol ⁻¹
Correct answer
A. 1.26 10^3 ⁻¹ ~cm ^2 ~mol ⁻¹
Step-by-step solution
aligned & = 1000 k c & = 1000 ~cm ^3 ~L ⁻¹ 1.26 10⁻² ⁻¹ ~cm ⁻¹ 0.01 ~mol ~L ⁻¹ & =1.26 10^3 ⁻¹ ~cm ^2 ~mol ⁻¹ aligned