Calculate current in ampere required to deposit 4.8 ~g Cu from it's salt solution in 30 minutes. [ . Molar mass of . Cu =63.5 ~g ~mol ⁻¹ ]

Step-by-step solution

aligned & Cu _ ( s ) ²⁺+2 e ⁻ Cu _ ( s ) & Mole ratio = 1 ~mol 2 ~mole ⁻ & W = I ( A ) t ( s ) 96500 ( C / mol e ⁻ ) mole ratio molar mass & 4.8 ~g = I ( A ) 30 60 96500 ( C / mol e ⁻ ) 1 ~mol 2 ~mol e ⁻ 63.5 ~g ~mol ⁻¹ & I ( A )= 4.8 96500 2 63.5 30 60 =8.1 ~A aligned