Which is the weight of A1 deposited at cathode when 1 ampere current is passed through molten AlCl ₃ for 9650 seconds? (At mass of Al =27 )

Step-by-step solution

aligned & Number of equivalents of Al deposited = I . t F & = 1 9650 96500 =0.1 & Number. Of equivalents = moles n _ factor & +3 AlCl ₃ Al _ factor =3 & 0.1= moles 3 & moles of Al =0.1 / 3 & mass of Al = 0.1 3 27=0.9 ~g aligned