MHT CET202122 Sep 2021Evening ShiftChemistryElectrochemistryActual
How many Faraday of electricity is required to deposit 0.8 ~g of calcium at cathode by the electrolysis of CaCl ₂ ?
Options
- A4 ~F
- B0.04 ~F
- C2.5 ~F
- D2 ~F
Correct answer
B. 0.04 ~F
Step-by-step solution
aligned & Ca ²⁺ Ca _ ( s ) & nf =2 & moles of calcium = 0.8 40 =2 10⁻² & no. of equivalents of calcium & = moles nf & =2 10⁻² 2 & =4 10⁻²=0.04 aligned To deposit 1 equivalent of electrolyte 1 Faraday electricity is required. To deposit 0.04 equivalents of electrolyte, 0.04 ~F electricity is required.