MHT CET202121 Sep 2021Morning ShiftChemistryElectrochemistryActual
The molar conductivity of 0.4 M KCl solution is 2.5 10^5 ⁻¹ cm ^2 ~mol ⁻¹ . What is the resistivity of solution?
Options
- A2.1 10^2
- B2.5 10^2
- C1 10⁻²
- D2.8 10⁻²
Correct answer
C. 1 10⁻²
Step-by-step solution
aligned & _ m = k 1000 M & 2.5 10^5= k 1000 0.4 & Conductivity ( k )= 1 ( resistivity ) & = 2.5 10^5 0.4 1000 & =100 ⁻¹ ~cm ⁻¹ & = 1 k = 1 100 =10⁻² cm aligned