MHT CET202020 Oct 2020Morning ShiftChemistryElectrochemistryActual
Molar conductivity of 0.01 M HCl solution is 400 0 ⁻¹ ~cm ² ~mol ⁻¹ . Calculate the conductivity of HCl solution.
Options
- A4 0 10⁻⁴ ⁻¹ ~cm ⁻¹
- B8 0 10⁻² ⁻¹ ~cm ⁻¹
- C2 5 10⁻² ⁻¹ ~cm ⁻¹
- D4 0 10⁻³ ⁻¹ ~cm ⁻¹
Correct answer
D. 4 0 10⁻³ ⁻¹ ~cm ⁻¹
Step-by-step solution
C =0.01 ~M , =400.0 ~ ⁻¹ ~cm ² ~mol ⁻¹ k =? = 1000 ~k C k = C 1000 k = 400.0 0.01 1000 =4.0 10⁻³ ⁻¹ ~cm ⁻¹