MHT CET202016 Oct 2020Evening ShiftChemistryElectrochemistryActual
If resistivity of 0.8 M KCl solution is 2 5 10⁻³ cm . Calculate molar conductivity of solution?
Options
- A3 10⁵ ⁻¹ ~cm ² ~mol ⁻¹
- B2 10⁵ ⁻¹ ~cm ² ~mol ⁻¹
- C4 10⁵ ⁻¹ ~cm ² ~mol ⁻¹
- D5 10⁵ ⁻¹ ~cm ² ~mol ⁻¹
Correct answer
D. 5 10⁵ ⁻¹ ~cm ² ~mol ⁻¹
Step-by-step solution
(A) array l Conductivity ( k )= 1 resistivity = 1 2.5 10⁻³ cm =0.4 10³ ⁻¹ ~cm ⁻¹ Molar conductivity ( _ m )= 1000 k C = 1000 ~cm ³ ~L ⁻¹ 0.4 10³ ⁻¹ ~cm ⁻¹ 0.8 ~mol ~L ⁻¹ array