MHT CET20192 May 2019Morning ShiftChemistryElectrochemistryActual
The resistance of 1 10 M solution is 2.5 × 10 3 o h m . What is the molar conductivity of solution? (cell constant = 1.25 c m - 1 )
Options
- A3.5 o h m - 1 c m 2 m o l - 1
- B5.0 o h m - 1 c m 2 m o l - 1
- C2.5 o h m - 1 c m 2 m o l - 1
- D2.0 o h m - 1 c m 2 m o l - 1
Correct answer
B. 5.0 o h m - 1 c m 2 m o l - 1
Step-by-step solution
cell constant, 1 a = 1.25 c m - 1 Resistance, R = 2.5 × 1 0 3 o h m We know that, R = ρ × 1 a ⇒ R = 1 κ × 1 a ⇒ κ = 5 × 1 0 - 4 c m - 1 o h m - 1 So, molar conductivity, λ m = κ × 1000 M = 5 × 1 0 - 4 × 1 0 3 1 10 = 5 d m - 3 c m 2 m o l - 1 = 5.0 d m - 1 c m 2 m o l - 1