How many moles of potassium chlorate are heated to produce 11 2 L oxygen at STP ?

Step-by-step solution

The balanced chemical equation for the decomposition of potassium chlorate is: 2KClO₃ 2KCl + 3O₂ At STP, the volume of 1 mole of an ideal gas is 22 4 L. Number of moles of O₂ produced is: n(O₂) = 11 2 22 4 = 1 2 mole From the stoichiometry of the reaction, 3 moles of O₂ are produced from 2 moles of KClO₃ . Therefore, the number of moles of KClO₃ required to produce 1 2 mole of O₂ is: n(KClO₃) = 2 3 n(O₂) = 2 3 1 2 = 1 3 mole Answer: 1 3 mole