Chlorine has two isotopes ³⁵ Cl and ³⁷ Cl with average atomic mass of 35.5 . What is the ratio of their relative abundance respectively?

Step-by-step solution

Average atomic mass (atomic mass of ³⁵ Cl percentage) = + atomic mass of ³⁷ Cl percentage 100 Let the % abundance of ³⁵ Cl isotope =x . % abundance of ³⁷ Cl isotope =100-x . Average atomic mass =35.5 From formula, average atomic mass = 35 x+37 (100-x) 100 =35.5 array ll & 35 x+3700-37 x=35.5 100 & -2 x=-3700+3550 & -2 x=-150 & x=75 % and (100-x)=25 % array Ratio of relative abundance = % abundance of ³⁵ Cl % abundance of ³⁷ Cl = 75 25 =3: 1