MHT CET20249 May 2024Morning ShiftChemistrySome Basic Concepts of ChemistryActual
What is the volume occupied by 1 molecule of water, if its density is 1 ~g ~cm ⁻³ ?
Options
- A9.0 10⁻²³ ~cm ^3
- B2.98 10⁻²³ ~cm ^3
- C6.023 10⁻²³ ~cm ^3
- D5.50 10⁻²³ ~cm ^3
Correct answer
B. 2.98 10⁻²³ ~cm ^3
Step-by-step solution
Mass of 6.022 10²³ molecules of water =1.8 ~g Mass of 1 molecule of water aligned & = 18 ~g 1 6.022 10²³ =2.98 10⁻²³ ~g & Density = mass volume aligned Volume occupied by 1 molecule of water = mass density = 2.98 10⁻²³ ~g 1 ~g ~cm ⁻³ =2.98 10⁻²³ ~cm ^3