MHT CET20244 May 2024Evening ShiftChemistrySome Basic Concepts of ChemistryActual
Calculate the molar mass of solute when 4 g of it dissolved in 1 dm ^3 . solvent has osmotic pressure 2 atm at 300 ~K . [ R =0 . 0 82 dm ^3 ~atm ~K ⁻¹ ~mol ⁻¹ ]
Options
- A49.2 ~g ~mol ⁻¹
- B44.5 ~g ~mol ⁻¹
- C54.2 ~g ~mol ⁻¹
- D56.4 ~g ~mol ⁻¹
Correct answer
A. 49.2 ~g ~mol ⁻¹
Step-by-step solution
aligned M ₂ & = W ₂ RT V & = 4 ~g 0.082 dm ^3 ~atm ~K ⁻¹ ~mol ⁻¹ 300 ~K 2 ~atm 1 dm ^3 & =49.2 ~g ~mol ⁻¹ aligned