Find the empirical formula of organic compound if it contains 18.6 % C , 1 55 % H , 55 04 % chlorine ? (atomic mass C =12, H =1, Cl =35 5, O =16 )

Step-by-step solution

The sum of the percentage of carbon, hydrogen, and chlorine is not 100 % Hence the rest of the part of the compound is oxygen percentage of oxygen =100-(18.6+1.55+55.04)=24.81 % Simplest ratio =1: 1: 1: 1 Hence empirical formula = CHCIO Empiraical formula weight =12 1+1 1+35.5 1+16 1=64.5 molecular mass empirical mass = 129 64.5 =2 Therefore molecular formula = n ( Empiricalformula ) Molecular formula =2 ( CHCIO ) Molecular formula C ₂ H ₂ Cl ₂ O ₂